Definition
Suppose that is a -module with a basis . Then the character of is defined by
Proposition
The following holds.
- , and it’s called the degree of .
- , if are conjugate.
- , thus is a real number iff is conjugate to .
- Suppose is an element with order , then is a sum of -th roots of unity.
- iff .
- .
- If is a character, then is also a character. And is irreducible iff is irreducible. Thus we know that the determinant of the character table is real or purely imaginary.
Regular Character
Definition
The regular character is the character of regular representation, denoted as .
Remark. There are some easy properties:
- ,
- .
Proposition
Suppose that , then the character of is equal to the sum of the characters of .
Thus we know
where are characters of a complete set of non-isomorphic irreducible -modules.
Permutation character
Definition
If is a subgroup of , there is an easy construction using the permutation module which produces a character of degree , denoted as .
Note that Furthermore, since there is a trivial module , we know that
is a character of .
(does not read)
Inner product of character
As the set of all functions from finite group to form a vector space, we can define an inner product on it.
Definition
Suppose that and are functions from to . Define
Remark. The “average trick” is useful to define functions about the group. Recall “alternative proof” of Maschke’s theorem.
More precisely, we can define the inner product of characters:$$ \bigl<\chi,\psi\bigr>=\frac{1}{|G|}\sum_{g\in G}\chi(g)\overline{\psi(g)}=\sum_{i=1}^{l}\frac{\chi(g_i)\psi(g_i^{-1})}{C_G(g_i)}.
> [!proposition] > > There is $\bigl<\chi,\psi\bigr> = \bigl<\psi,\chi\bigr>$. In the other word, $\bigl<\chi,\psi\bigr>$ is a real number. > [!theorem] > > The irreducible characters form an orthonormal set of vectors in the vector space of functions from $G$ to $\mathbb C$. For any irreducible characters $\chi$ and $\psi$, if they are isomorphic, $\bigl<\chi,\psi\bigr>=1$. Otherwise $\bigl<\chi,\psi\bigr>=0$. **Proof.** The proof is a little bit complex. - Take $W_1=\oplus_{i=1}^d V_i$ where $V_i$ are isomorphic to an irreducible module $V$, and $V=V_1\oplus V_2$. Decompose $e$ as $e_1+e_2$, where $e_1\in W_1,e_2\in W_2$ and $W_1,W_2$ are $\mathbb CG$-modules with having no common factor. - Write $e_1$ in the linear combination of $g\in G$, by computing trace of a special linear transformation. The answer is $e_1=\frac{1}{|G|}\sum_{g\in G} \chi(g^{-1})g$, where $\chi$ is the character of $W_1$. - Consider the coefficient of 1 of $e_1$, and we know $\bigl<\chi,\chi\bigr>=\chi(1)$ for the character of $W_1$. - Then $d^2=\bigl<\chi_{W_1},\chi_{W_1}\bigr>=d^2\bigl<\chi_V,\chi_V\bigr>$ and so $\bigl<\chi_V,\chi_V\bigr>=1$. Therefore, we complete the proof. #### Application - $\chi=\sum d_i\chi_i$, where $\chi_i$ are irreducible $\mathbb CG$-module, then $\bigl<\chi,\chi\bigr>=\sum d_i^2$. - $\chi$ is an irreducible $\mathbb CG$-module iff $\bigl<\chi,\chi\bigr>=1$. - Suppose $U$ and $V$ are $\mathbb CG$-modules with characters $\chi$ and $\psi$, then: - $U\cong V$ iff $\chi=\psi$ - $\bigl<\chi,\psi\bigr>=\dim\mathrm{Hom}_{\mathbb CG}(U,V)$ - Decomposing $\mathbb CG$-module: Suppose $V$ is any $\mathbb CG$-module and $\chi$ is an irreducible character of $G$, then$$ V(\sum_{g\in G} \chi(g^{-1})g) $$is equal to the sum of those $\mathbb CG$-submodule of $V$ which have character $\chi$. (using $e_1$ to make a filter)